COA Tutorial
Basic CO and Design
Computer Instructions
Digital Logic Circuits
Map Simplification
Combinational Circuits
Flip - Flops
Digital Components
Register Transfer
Micro-Operations
Memory Organization
COA_Misc
- Booth's Multiplication Algorithm
- Branch Instruction in Computer Organization
- Data Representation in Computer Organization
- ALU and Data Path in Computer Organization
- External memory in Computer Organization
- Structured Computer Organization
- Types of Register in Computer Organization
- Secondary Storage Devices in Computer Organization
- Types of Operands in Computer Organization
- Serial Communication in Computer organization
- Addressing Sequencing in Computer Organization
- Simplified Instructional Computer (SIC)
- Arithmetic Instructions in AVR microcontroller
- Conventional Computing VS Quantum Computing
- Instruction set used in Simplified Instructional Computer
- Branch Instruction in AVR microcontroller
- Conditional Branch instruction in AVR Microcontroller
- Data transfer instruction in AVR microcontroller
- Difference between Memory-based and Register-based addressing modes
- Difference between 1's complement Representation and 2's complement Representation
- CALL Instructions and Stack in AVR Microcontroller
- Difference between Call and Jump Instructions
- Overflow in Arithmetic Addition in Binary number System
- Horizontal Micro-programmed Vs. Vertical Micro-programmed Control Unit
- Hardwired Vs. Micro-programmed Control Unit
- Non-Restoring Division Algorithm for Unsigned Integer
- Restoring Division Algorithm for Unsigned Integer
- Debugging a Machine-level Program
- Dependencies and Data Hazard in pipeline in Computer Organization
- Execution, Stages and Throughput in Pipeline
- Types of Pipeline Delay and Stalling
- Timing Diagram of MOV Instruction
- Advantages and Disadvantages of Flash Memory
- Importance/Need of negative feedback in amplifiers
- Anti-Aliasing - Computer Graphics
- Bus Arbitration in Computer Organization
- Convert a number from Base 2 (Binary) to Base 6
- Cache Coherence
- EHCI
- Cache Memory and Virtual Memory
- Electrical Potential and Potential Difference
- RAM and Cache
- SIM and RIM instructions in 8085 processor
- Clusters in Computer Organization
- Data Types and Addressing Modes of 80386/80386DX Microprocessor
Arithmetic Pipeline
Arithmetic Pipelines are mostly used in high-speed computers. They are used to implement floating-point operations, multiplication of fixed-point numbers, and similar computations encountered in scientific problems.
To understand the concepts of arithmetic pipeline in a more convenient way, let us consider an example of a pipeline unit for floating-point addition and subtraction.
The inputs to the floating-point adder pipeline are two normalized floating-point binary numbers defined as:
X = A * 2a = 0.9504 * 103 Y = B * 2b = 0.8200 * 102
Where A and B are two fractions that represent the mantissa and a and b are the exponents.
The combined operation of floating-point addition and subtraction is divided into four segments. Each segment contains the corresponding suboperation to be performed in the given pipeline. The suboperations that are shown in the four segments are:
- Compare the exponents by subtraction.
- Align the mantissas.
- Add or subtract the mantissas.
- Normalize the result.
We will discuss each suboperation in a more detailed manner later in this section.
The following block diagram represents the suboperations performed in each segment of the pipeline.
Note: Registers are placed after each suboperation to store the intermediate results.
1. Compare exponents by subtraction:
The exponents are compared by subtracting them to determine their difference. The larger exponent is chosen as the exponent of the result.
The difference of the exponents, i.e., 3 - 2 = 1 determines how many times the mantissa associated with the smaller exponent must be shifted to the right.
2. Align the mantissas:
The mantissa associated with the smaller exponent is shifted according to the difference of exponents determined in segment one.
X = 0.9504 * 103 Y = 0.08200 * 103
3. Add mantissas:
The two mantissas are added in segment three.
Z = X + Y = 1.0324 * 103
4. Normalize the result:
After normalization, the result is written as:
Z = 0.1324 * 104